6x^2+x-2=100

Solution for 6x^2+x-2=100 equation:

6x^2+x-2=100

We move all terms to the left:

6x^2+x-2-(100)=0

We add all the numbers together, and all the variables

6x^2+x-102=0

a = 6; b = 1; c = -102;
Δ = b2-4ac
Δ = 12-4·6·(-102)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2449}}{2*6}=\frac{-1-\sqrt{2449}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2449}}{2*6}=\frac{-1+\sqrt{2449}}{12}
$